Consider the following statements for diboran | vedclass

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(A) In diborane $(B_2H_6)$,each boron atom undergoes $sp^3$ hybridization.In the bridged structure of diborane,the $B-H-B$ angle is $83^{\circ}$,not $

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$1, 3$ and $4$ are correct

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(A) In diborane $(B_2H_6)$,each boron atom undergoes $sp^3$ hybridization.In the bridged structure of diborane,the $B-H-B$ angle is $83^{\circ}$,not $180^{\circ}$.Each boron atom is linked to two terminal hydrogen atoms via $2c-2e$ bonds and two bridged hydrogen atoms via $3c-2e$ bonds. Thus,statement $3$ is correct.Diborane has $8$ atoms ($2$ Boron and $6$ Hydrogen). Total valence electrons = $2 	imes 3 + 6 	imes 1 = 12$. These $12$ electrons are involved in bonding ($4$ terminal $B-H$ bonds and $2$ bridged $B-H-B$ bonds). Thus,statement $4$ is correct.Therefore,statements $1, 3,$ and $4$ are correct.

Consider the following statements for diborane $(B_2H_6)$:
$1.$ Boron is approximately $sp^3$ hybridized.
$2.$ $B-H-B$ angle is $180^{\circ}$.
$3.$ There are two terminal $B-H$ bonds for each boron atom.
$4.$ There are only $12$ bonding electrons available.
Which of these statements are correct?

Similar Questions

Borax is converted into crystalline boron by the following steps :
$Borax$ $\xrightarrow{HCl} (X)$ $\xrightarrow{\Delta} B_2O_3$ $\xrightarrow{\Delta, Y} B$
Identify $X$ and $Y$ respectively.

The correct statements among $I$ to $III$ regarding group $13$ element oxides are,
$I$. Boron trioxide is acidic
$II$. Oxides of aluminium and gallium are amphoteric
$III$. Oxides of indium and thallium are basic

In borax, the number of $B-O-B$ links and $B-OH$ bonds present are, respectively:

Explain the following:
$(1)$ Aluminum forms $[AlF_6]^{3-}$ ion but boron does not form $[BF_6]^{3-}$ ion.
$(2)$ $PbX_2$ is more stable than $PbX_4$.

Which reactions can be used to prepare diborane?
$I.$ $3NaBH_4 + 4BF_3 \xrightarrow{\text{ether}} 2B_2H_6 + 3NaBF_4$
$II.$ $2NaBH_4 + I_2 \to B_2H_6 + 2NaI + H_2$
$III.$ $2BF_3 + 6NaH \xrightarrow{450 \ K} B_2H_6 + 6NaF$

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Consider the following statements for diborane $(B_2H_6)$:$1.$ Boron is approximately $sp^3$ hybridized.$2.$ $B-H-B$ angle is $180^{\circ}$.$3.$ There are two terminal $B-H$ bonds for each boron atom.$4.$ There are only $12$ bonding electrons available.Which of these statements are correct?